(2x+5)(3x^2-20x+12)=0

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Solution for (2x+5)(3x^2-20x+12)=0 equation: 


Simplifying
(2x + 5)(3x2 + -20x + 12) = 0

Reorder the terms:
(5 + 2x)(3x2 + -20x + 12) = 0

Reorder the terms:
(5 + 2x)(12 + -20x + 3x2) = 0

Multiply (5 + 2x) * (12 + -20x + 3x2)
(5(12 + -20x + 3x2) + 2x * (12 + -20x + 3x2)) = 0
((12 * 5 + -20x * 5 + 3x2 * 5) + 2x * (12 + -20x + 3x2)) = 0
((60 + -100x + 15x2) + 2x * (12 + -20x + 3x2)) = 0
(60 + -100x + 15x2 + (12 * 2x + -20x * 2x + 3x2 * 2x)) = 0
(60 + -100x + 15x2 + (24x + -40x2 + 6x3)) = 0

Reorder the terms:
(60 + -100x + 24x + 15x2 + -40x2 + 6x3) = 0

Combine like terms: -100x + 24x = -76x
(60 + -76x + 15x2 + -40x2 + 6x3) = 0

Combine like terms: 15x2 + -40x2 = -25x2
(60 + -76x + -25x2 + 6x3) = 0

Solving
60 + -76x + -25x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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